输出数字之内的完全数

x=eval(input())
#代码开始
for i in range(2,x+1):
    sum = 0
    for j in range(1,i):#分解因子，求i的因子和
        if i%j == 0:
            sum +=j
    if i == sum:
        print(i)

#代码结束

输出阶乘等式

x=eval(input())
#代码开始

for i in range(1,x+1):
    sum = 1
    k = ""
    for j in range(1,i+1):
        sum *=j
        if j == 1:
            k = k+str(j)
        else:
            k = k+'*'+str(j)
        
    print("{}!={}={}".format(i,k,sum))

#代码结束

输出符合要求的数字

x=eval(input())
#代码开始
list = [0,1,2,3,4,5,6,7,8,9]
a = list[0:(x+1)]
count = 0
for i in range(1,x+1):
    for j in range(0,x+1):
        if a[j] == a[i]:
            continue
        else:
            s = str(a[i])+str(a[j])
        for k in range(0,x+1):
            if a[k] == a[i] or a[k] == a[j]:
                continue
            else:
                m = s+str(a[k])+' '
                count += 1
                print(m,end='' if count%10 != 0 else "\n" )

#代码结束

鸡兔同笼问题

t=eval(input())
j=eval(input())
#代码开始
# x:兔子，y:鸡
if (j-2*t)%2 == 0:
    x = (j-2*t)*0.5
    y = t-x
    print("鸡{}只兔子{}只".format(int(y),int(x)))
else:
    print("无解")
#代码结束

剩余最短木料

s=eval(input())
#代码开始
if s<42:
    print("木料太短，请重新输入")
else:
    x1 = (s-42)//23 #取商
    x2 = (s-42)%23 #取余
    if x2+x1*4<19:
        n1 = 1
        n2 = x1+1
        zx = x2
    elif x2>=19:
        n1 = 2
        n2 = x1+1
        zx = x2-19
    else:
        for i in range(1,x1+1):
            if x2+4*i>=19:
                n1 = i+2
                n2 = x1-i+1
                zx = (x2+4*i)%19
                break
#代码结束
print("19米{}段,23米{}段,剩余{}米".format(n1,n2,zx))

打印图形

zm=input("")
#代码开始
zn = ord(zm) #67
k = zn-65
for i in range(0,k+1):
    print(' '*(k-i),end='')
    for j in range(0,i+1):
        print(chr(65+j),end='')
    for n in range(i,0,-1):
        print(chr(64+n),end='')
    print('\n',end='')
print('')
#代码结束

逻辑推断

#代码开始
for a in range(0,2):
    for b in range(0,2):
        for c in range(0,2):
            for d in range(0,2):
                if a+b+c+d == 1: #只有一个罪犯
                    if (b==1 or c==1 or d==1)+2*(b==0 and c==1)+(a==1 or d==1)==2:
                        if a == 1:
                            print('A是罪犯')
                        elif b == 1:
                            print('B是罪犯')
                        elif c == 1:
                            print('C是罪犯')
                        elif d == 1:
                            print('D是罪犯')
 
 #代码结束

多人唐诗作品

import re
f1=open("sy6//唐诗.txt","r",encoding="utf-8")

#代码开始
content = f1.read() #只读一次
while True:
    x=input("诗人姓名")
    def cha(i):
        t = re.findall("\d{3}"+i+'\:\S+',content)
        if i != '' and len(t) == 0:
            print("无作品")
        elif len(t) > 0:
            for k in t:
                print(k)
            print('一共'+str(len(t))+'首')
           
    cha(x)
    if x == '':
        break
#代码结束
f1.close()