Educoder：python实验七元组和集合

日期的转换x=input("输入日期")#开始date = {1:'January',2:'February',3:'March',4:'April',5:'May',6:'June',7:'July',8:'August',9:'September',10:'October',11:'November',12:'December'}k = x.split('/')m = date.get(int

伽希

3631人浏览 · 2021-12-09 22:00:00

伽希 · 2021-12-09 22:00:00 发布

日期的转换

x=input("输入日期")
#开始
date = {1:'January',2:'February',3:'March',4:'April',5:'May',6:'June',7:'July',8:'August',9:'September',10:'October',11:'November',12:'December'}
k = x.split('/')
m = date.get(int(k[1]))
y = m+' '+k[2]+','+k[0]
z = k[2]+' '+m+','+k[0]
#结束
print("美式格式"+y)
print("英式格式"+z)

计算购买饮品金额

cp=(("悠哉悠哉",18),("人间烟火",17),("蔓越阑珊",17),("抹茶葡提",16),("幽兰拿铁",16),("  翠翠  ",13),("浮生半日",15),("筝筝纸鸢",16),("声声乌龙",15),("风栖绿桂",12),("素颜锡兰",13),("烟火易冷",15))
#代码开始
k = 1
c = 0
for i in range(len(cp)):
    if k<10:
        z = ' '+str(k)
    else:
        z = str(k)
    for j in range(len(cp[0])):
        z += str(cp[i][j])
    print(z)
    k += 1
while True:
    a = int(input("请选择饮品"))
    if a == 0:
        break
    b = int(input("请输入数量"))
    c += cp[a-1][1]*b
print("应付"+str(c)+"元")
#代码结束

判断句子是否每个英文字母起码出现一次

x=input("")
#代码开始
a = set(x)
b = set('QWERTYUIOPASDFGHJKLZXCVBNMqwertyuiopasdfghjklzxcvbnm')
c = a&b
if len(c)>=24:
    print('True')
else:
    print('False')

#代码结束

集合的运算

hd1=set()
hd2=set()
gh=input("")
lb=gh.split(',')
for x in lb:
    hd1.add(eval(x))
gh=input("")
lb=gh.split(',')
for x in lb:
    hd2.add(eval(x))
#代码开始
hd3 = hd1&hd2
hd4 = hd1-hd2
hd5 = hd2-hd1
#代码结束
print("两项活动都参加",hd3)
print("只参加活动1",hd4)
print("只参加活动2",hd5)