POJ 2117 Electricity (去点后的联通块数 tarjan终极模板)
https://vjudge.net/problem/POJ-2117tarjan终极模板solve():求桥solve1():求割点solve2():求去掉一个点后联通块数#include<iostream>#include<cstring>#include<cstdio>#include<algorithm>#inc...
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https://vjudge.net/problem/POJ-2117
tarjan终极模板
solve():求桥
solve1():求割点
solve2():求去掉一个点后联通块数
#include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
#include<vector>
#include<set>
#include<map>
#include<queue>
#include<cmath>
#define ll long long
#define mod 1000000007
#define inf 0x3f3f3f3f
using namespace std;
const int maxn = 10005;
const int maxm = 100005;
struct edge
{
int to, next;
bool cut;
}e[maxm];
int head[maxn], cnt;
int low[maxn], dfn[maxn], stk[maxn];
int indexx, top;
bool vis[maxn];
bool cut[maxn];
int add_block[maxn];//删除一个点后增加的联通块数
int bridge;
void addedge(int u, int v)
{
e[cnt].to = v;
e[cnt].cut = 0;
e[cnt].next = head[u];
head[u] = cnt ++;
}
void tarjan(int u, int pre)
{
low[u] = dfn[u] = ++ indexx;
stk[top ++] = u;
vis[u] = 1;
int son = 0;
int pre_cnt = 0;
for(int i = head[u]; ~i; i = e[i].next)
{
int v = e[i].to;
if(v == pre && pre_cnt == 0)
{
pre_cnt ++;
continue;
}
if(! dfn[v])
{
son ++;
tarjan(v, u);
if(low[u] > low[v])
low[u] = low[v];
if(low[v] > dfn[u])
{
bridge ++;
e[i].cut = 1;
e[i^1].cut = 1;
}
if(u != pre && low[v] >= dfn[u])
{
cut[u] = 1;
add_block[u] ++;
}
}
else if(low[u] > dfn[v])
low[u] = dfn[v];
}
if(u == pre && son > 1) cut[u] = 1;
if(u == pre) add_block[u] = son - 1;
vis[u] = 0;
top --;
}
map<int, int> mapit;//判断重边
inline bool isHash(int u, int v)
{
if(u == v) return 1;
if(mapit[u*maxn+v]) return 1;
if(mapit[v*maxn+u]) return 1;
mapit[u*maxn+v] = mapit[v*maxn+u] = 1;
return 0;
}
void solve(int n)//桥
{
memset(dfn, 0, sizeof(dfn));
memset(vis, 0, sizeof(vis));
memset(add_block, 0, sizeof(add_block));
memset(cut, 0, sizeof(cut));
indexx = top = 0;
bridge = 0;
for(int i = 1; i <= n; i ++)
{
if(! dfn[i])
tarjan(i, i);
}
printf("%d critical links\n", bridge);
vector<pair<int, int> > ans;
for(int u = 1; u <= n; u ++)
{
for(int i = head[u]; ~i; i = e[i].next)
{
if(e[i].cut && e[i].to > u)
{
ans.push_back(make_pair(u, e[i].to));
}
}
}
sort(ans.begin(), ans.end());
int ansize = ans.size();
for(int i = 0; i < ansize; i ++)
{
printf("%d - %d\n", ans[i].first - 1, ans[i].second - 1);
}
printf("\n");
}
void solve1(int n)//割点
{
memset(dfn, 0, sizeof(dfn));
memset(vis, 0, sizeof(vis));
memset(add_block, 0, sizeof(add_block));
memset(cut, 0, sizeof(cut));
indexx = top = 0;
bridge = 0;
for(int i = 1; i <= n; i ++)
{
if(! dfn[i])
tarjan(i, i);
}
int ans = 0;
for(int i = 1; i <= n; i ++)
if(cut[i]) ans ++;
printf("%d\n", ans);
}
void solve2(int n)//删除一个点后,图中最多有多少个联通块
{
memset(dfn, 0, sizeof(dfn));
memset(vis, 0, sizeof(vis));
memset(add_block, 0, sizeof(add_block));
memset(cut, 0, sizeof(cut));
indexx = top = 0;
bridge = 0;
int num = 0;//记录本来的联通块数
for(int i = 1; i <= n; i ++)
{
if(! dfn[i])
{
tarjan(i, i);
num ++;
}
}
int ans = 0;
for(int i = 1; i <= n; i ++)
ans = max(ans, num + add_block[i]);
printf("%d\n", ans);
}
int main()
{
int n, m;
while(scanf("%d%d", &n, &m) != EOF && (n + m))
{
memset(head, -1, sizeof(head));
cnt = 0;
int u, v;
//mapit.clear();
while(m --)
{
scanf("%d%d", &u, &v);
u ++, v ++;
addedge(u, v);
addedge(v, u);
}
solve2(n);
}
return 0;
}
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