洛谷P3375

#include <iostream>
#include <cstring>

using namespace std;
const int N = 1000010;
char s1[N], s2[N];
int ne[N]; // ne[i]:s2前i位组成的子串的最长相等前缀后缀的长度

int main()
{
	s1[0] = ' ', s2[0] = ' ';
	cin >> s1+1 >> s2+1; // 为方便可将字符串下标定义为从1开始
	int  len1 = strlen(s1) - 1, len2 = strlen(s2) - 1;

	for(int i = 2, j = 0; i <= len2; i++)
	{
		while(j && s2[i] != s2[j+1]) j = ne[j]; //若匹配不成功， 则移动字符串进行再次匹配
		if(s2[i] == s2[j+1]) j++;
		ne[i] = j;
	}

	for(int i = 1, j = 0; i <= len1; i++)
	{
		while(j && s1[i] != s2[j+1]) j = ne[j];
		if(s1[i] == s2[j+1]) j++;
		if(j == len2) // 成功匹配
		{
			cout << i - j + 1 << endl;
			j = ne[j];
		}
	}

	for(int i = 1; i <= len2; i++) cout << ne[i] << ' ';
	return 0;
}