flutter 找出两个数组中不同的元素

List arr1=[2,4,6,8,10,1,3];List arr2=[2,4,6,8,10,12,14];List newArr=[];arr1.forEach((item){if(!arr2.contains(item)){newArr.add(item);}});arr2.forEach((item){if(!arr1.contains(item)){newArr.add(item);}

相思碎.

2694人浏览 · 2021-11-24 16:48:01

相思碎. · 2021-11-24 16:48:01 发布

List arr1=[2,4,6,8,10,1,3];
List arr2=[2,4,6,8,10,12,14];
List newArr=[];
arr1.forEach((item){
    if(!arr2.contains(item)){
        newArr.add(item);
    }
});
arr2.forEach((item){
    if(!arr1.contains(item)){
        newArr.add(item);
    }
});

print('数组中不同的元素是：'+newArr.join(','));