Every derived table must have its own alias(sql语句错误解决方法)
1. 在做多表查询,或者查询的时候产生新的表的时候会出现这个错误:Every derived table must have its own alias(每一个派生出来的表都必须有一个自己的别名)。eg:delete from stockwhere (org_id,material_id,state)in(SELECT * from(select org_id,ma...
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1. 在做多表查询,或者查询的时候产生新的表的时候会出现这个错误:Every derived table must have its own alias(每一个派生出来的表都必须有一个自己的别名)。
eg:
delete from stock
where (org_id,material_id,state)
in (SELECT * from
(select org_id,material_id, state from stock WHERE state = 1 group by org_id,material_id,state having count(*) > 1)
)
当执行这条sql语句的时候就会出现Every derived table must have its own alias;
2. 这条sql:
(select org_id,material_id, state from stock WHERE state = 1 group by org_id,material_id,state having count(*) > 1)
就会产生一张新的表,和前面的表stock联合查询,但是mysql要求每一个派生出来的表都必须有一个自己的别名,那我给派生表加上别名即可;
eg:修改后的sql,直接在新生产的表中加入 他的别命名就行(“as a”或者“a”),“a”为新表的别名
delete from stock
where (org_id,material_id,state) in
(SELECT * from (select org_id,material_id, state
from stock WHERE state = 1 group by org_id,material_id,state having count(*) > 1) as a )
这样就解决了问题;
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