el-table 排序
el-table排序
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在项目中使用el-table的默认排序功能产生问题,如按照数字排序,当数字有多位时,只按照第一位数字排序问题,
问题复现:
添加代码修改:
主要是这一行sort-method,传递的item.prop就是el-table-column 中的prop字段
:sort-method="(a, b) => sortMethod(item.prop, a, b)"
<el-table :data="tableData" style="width: 100%;background:transparent;" :height="tableMaxHeight"
:header-cell-style='headerCellStyle' :header-row-style='headerRowStyle' :row-style='rowStyle'
:cell-style="rowCellStyle" class="dealljtable projecttable tableindexstyle"
@cell-mouse-enter="handlerTableOver" @cell-mouse-leave="handlerTableOut" >
<el-table-column label="" type="index" width="60">
</el-table-column>
<el-table-column :min-width="item.width || 80" v-for="item in headerKeys" :key="item.label"
align="center" :fixed="item.fixed" :prop="item.prop" :minWidth="item.minWidth"
:sortable="item.label === '成交套数' ? true : false"
:sort-method="(a, b) => sortMethod(item.prop, a, b)"
:sort-orders="['ascending', 'descending']">
<template slot="header">
<div class="header-wrap">
<span class="label">{{ item.label }}</span>
<div class="unit" v-if="item.unit">({{ item.unit }})</div>
</div>
</template>
<template slot-scope="scope">
<div class="handle-icon palterow" v-if="scope.column.property === 'caption'">
{{ scope.row[scope.column.property] != null ? scope.row[scope.column.property] : '-' }}---
</div>
<div v-else class="handle-icon">
{{ scope.row[scope.column.property] != null ? scope.row[scope.column.property] : '-' }}
</div>
</template>
</el-table-column>
<template slot="empty">
<NoData></NoData>
</template>
</el-table>
data(){
return{
headerKeys: [
{
label: '项目名称',
key: '',
unit: '',
prop: "caption",
minWidth: '100',
},
{
label: '建筑年代',
key: '',
unit: '',
prop: "buildingYear",
minWidth: '80',
},
{
label: '成交套数',
key: '',
unit: '套',
prop: "tradeCount",
minWidth: '90',
sortable: true,
},
{
label: '成交均价',
key: '',
unit: '元/m²',
prop: "tradePrice",
minWidth: '100',
}, {
label: '成交金额',
key: '',
unit: '万元',
prop: "tradeMoney",
minWidth: '100',
},
],
}
}
methods: {
//sortMethod方法
sortMethod(key, a, b) {
let _a = a[key] ?? 0;
let _b = b[key] ?? 0;
return _a - _b;
},
}
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