方法一：使用forEach遍历

let list = ['a','b','c','d','e']
list.forEach((item,index)=>{
  if(item == 'c'){
    list.splice(index,1)
  }
})
console.log('forEach',list)

方法二：使用map

let list = ['a','b','c','d','e']
list = list.map(item=>{
  return item == 'c'?'':item
})
console.log('map',list)

方法三：使用filer，这是比较正确的方法

let list = ['a','b','c','d','e']
list = list.filter(item=>{
  return item != 'c'
})
console.log('filter',list)

方法四：使用Set，方法很蠢但是的确可以实现

let list = ['a','b','c','d','e']
let arr =  ['c']
let set1 = new Set(list)
let set2 = new Set(arr)
//先将数组转为集合set，再利用set取差集
let newList = [...set1].filter(item=>{
  return !set2.has(item)
})
console.log('set',newList)

输出展示