前言:

三消算法首要实现的就是找到所有三个或三个以上的同样颜色,所以我们思路是:判断每个点进行上下左右四个方向移动后,能得到三个及以上的相连。

经过分析,当我们向一个方向移动时,会有四种情况符合条件,所以当一个点符合消除时,需要判断周围点的情况共有16种!

例如:当红色圈向右移动一格能消除时,他周围的情况必然时图下四种状态:

1.与右边两个绿圈消除

2.与右上方两个蓝圈消除

3.与右下方两个黄圈消除

4.与右边上下各一个绿色正方形消除。

所以,我们的要做的是:

第一步:

将图片转换成矩阵:

list_ = [["绿", "红", "红", "紫", "绿", "紫", "蓝"],
         ["紫", "紫", "绿", "黄", "绿", "蓝", "紫"],
         ["紫", "红", "紫", "红", "紫", "蓝", "黄"],
         ["蓝", "紫", "紫", "蓝", "黄", "紫", "绿"],
         ["红", "蓝", "绿", "紫", "黄", "蓝", "绿"]]

第二步:

从上往下,从左往右,遍历每一个点,并且遍历它周围的特定位置,判断是否移动该点,能和周围的点结合实现消除。

用于算法计算的坐标轴:

第三步:

代码实现:

list_ = [["绿", "红", "红", "紫", "绿", "紫", "蓝"],
         ["紫", "紫", "绿", "黄", "绿", "蓝", "紫"],
         ["紫", "红", "紫", "红", "紫", "蓝", "黄"],
         ["蓝", "紫", "紫", "蓝", "黄", "紫", "绿"],
         ["红", "蓝", "绿", "紫", "黄", "蓝", "绿"]]


# 横坐标为x,纵坐标为y
def main_method(list_):
    for x in range(7):
        for y in range(5):
            # 获取该坐标点的颜色
            c = list_[y][x]
            print(x, y, c)
            # 判断该坐标向右移是否满足(考虑越界问题,需判断坐标变换后是否在矩阵内)
            if ((y - 1) >= 0 and (x + 1) <= 6 and (
                    y + 1) <= 4 and list_[y - 1][x + 1] == c and list_[y + 1][x + 1] == c) or (
                    (x + 2) <= 6 and (x + 3) <= 6 and list_[y][x + 2] == c and list_[y][x + 3] == c) or (
                    (y - 1) >= 0 and (x + 1) <= 6 and (
                    y - 2) >= 0 and list_[y - 1][x + 1] == c and list_[y - 2][x + 1] == c) or (
                    (y + 1) <= 4 and (x + 1) <= 6 and (
                    y + 2) <= 4 and list_[y + 1][x + 1] == c and list_[y + 2][x + 1] == c):
                print("请将[%s,%s]右移" % (x, y))
                return [x, y, '右移']
            # 判断该坐标向左移是否满足
            elif ((y - 1) >= 0 and (x - 1) >= 0 and (
                    y + 1) <= 4 and list_[y - 1][x - 1] == c and list_[y + 1][x - 1] == c) or (
                    (x - 2) >= 0 and (x - 3) >= 0 and list_[y][x - 2] == c and list_[y][x - 3] == c) or (
                    (y - 1) >= 0 and (x - 1) >= 0 and (
                    y - 2) >= 0 and list_[y - 1][x - 1] == c and list_[y - 2][x - 1] == c) or (
                    (y + 1) <= 4 and (x - 1) >= 0 and (
                    y + 2) <= 4 and list_[y + 1][x - 1] == c and list_[y + 2][x - 1] == c):
                print("请将[%s,%s]左移" % (x, y))
                return [x, y, '左移']
            # 判断该坐标向上移是否满足
            elif ((y - 1) >= 0 and (x - 1) >= 0 and (
                    x + 1) <= 6 and list_[y - 1][x - 1] == c and list_[y - 1][x + 1] == c) or (
                    (y - 2) >= 0 and (y - 3) >= 0 and list_[y - 2][x] == c and list_[y - 3][x] == c) or (
                    (y - 1) >= 0 and (x - 1) >= 0 and (
                    x - 2) >= 0 and list_[y - 1][x - 1] == c and list_[y - 1][x - 2] == c) or (
                    (x + 1) <= 6 and (x + 2) <= 6 and (
                    y - 1) >= 0 and list_[y - 1][x + 1] == c and list_[y - 1][x + 2] == c):
                print("请将[%s,%s]上移" % (x, y))
                return [x, y, '上移']
            # 判断该坐标向下移是否满足
            elif ((y + 1) <= 4 and (x - 1) >= 0 and (
                    x + 1) <= 6 and list_[y + 1][x - 1] == c and list_[y + 1][x + 1] == c) or (
                    (y + 2) <= 4 and (y + 3) <= 4 and list_[y + 2][x] == c and list_[y + 3][x] == c) or (
                    (y + 1) <= 4 and (x - 1) >= 0 and (
                    x - 2) >= 0 and list_[y + 1][x - 1] == c and list_[y + 1][x - 2] == c) or (
                    (x + 1) <= 6 and (x + 2) <= 6 and (
                    y + 1) <= 4 and list_[y + 1][x + 1] == c and list_[y + 1][x + 2] == c):
                print("请将[%s,%s]下移" % (x, y))
                return [x, y, '下移']
            else:
                print("不满足")
                continue
    return ['无有效移动']


if __name__ == '__main__':
    main_method(list_)

运行结果:(起始坐标点为[0,0])

Logo

为开发者提供学习成长、分享交流、生态实践、资源工具等服务,帮助开发者快速成长。

更多推荐