已知三角形的三边长a,b,c,利用海伦公式求三角形面积

if语句代码:a = float(input("输入边长a:"))b = float(input("输入边长b:"))c = float(input("输入边长c:"))if a+b > c and a+c > b and b+c > a:s = (a+b+c)/2area = (s*(s-a)*(s-b)*(s-c))**0.5print("三角形的面积为:", area)el

keep the smile

10844人浏览 · 2021-11-20 11:15:31

keep the smile · 2021-11-20 11:15:31 发布

if语句

代码:

a = float(input("输入边长a:"))
b = float(input("输入边长b:"))
c = float(input("输入边长c:"))
if a+b > c and a+c > b and b+c > a:
    s = (a+b+c)/2
    area = (s*(s-a)*(s-b)*(s-c))**0.5
    print("三角形的面积为:", area)
else:
    print("不能构成三角形")

截图:

while语句

代码:

a = float(input("输入边长a:"))
b = float(input("输入边长b:"))
c = float(input("输入边长c:"))
while not (a+b > c and a+c > b and b+c > a):
    print("不能构成三角形,请重新输入")
    a = float(input("输入边长a:"))
    b = float(input("输入边长b:"))
    c = float(input("输入边长c:"))
s = (a+b+c)/2
area = (s*(s-a)*(s-b)*(s-c))**0.5
print("三角形的面积为:", area)

截图:

函数调用

代码:

def hailun(a, b, c):
    s = (a+b+c)/2
    area = (s*(s-a)*(s-b)*(s-c))**0.5
    return area
a = float(input("输入边长a:"))
b = float(input("输入边长b:"))
c = float(input("输入边长c:"))
while(a+b>c and a+c>b and b+c>a):
    area = hailun(a, b, c)
    print("三角形的面积为", area)
    break
else:
    print("不能构成三角形")

截图: